In a bb x bb cross

a.
100% of the offspring will have the bb genotype
c.
75% of the offspring will have the bb phenotype
b.
25% of the offspring will have the bb genotype
d.
50% of the offspring will have the bb phenotype

a.

100% of the offspring will have the Bb genotype

Explanation:

This cross involves a single gene that has two alternative forms called ALLELES. One allele is 'B' and the other is 'b'. In the cross, both parents are purebreeding or homozygous i.e. they contain identical alleles for a particular trait (BB and bb). Therefore, according to Mendel's law of segregation, the alleles of each parent will separate into gametes during meiosis.

Parent 'BB' will produce gametes containing allele 'B' while parent 'bb' will produce gametes containing allele 'b'. Each gametes will then combine randomly. Since only gametes B and b are produced by each parent, all the offsprings produced will have a heterozygous genotype: Bb. Hence, 100% of the F1 offsprings will possess Bb genotype.

x would be the most and the least would be y because there are more fruit   and seeds than flock z has insects