AUG is the start codon, and UAG, UGA, and UAA are the possible stop codons. The code on a human mRNA reads AUGCCCUUUAUGUAA.
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Which statements are true about this sequence?
Select all that apply.
Protein synthesis cannot start because there is no start codon.
The protein will have only four amino acids.
Two methionine amino acids will be in the protein chain.
The protein will have five amino acids.

The correct answer is -

Two methionine amino acids will be in the protein chain.

The protein will have five amino acids.

Explanation:

In protein synthesis, there are mRNA codons made up of the three bases known as triplet codons that form a specific amino acid during translation. There is a specific codon known as the starting codon that is AUG present at the beginning of almost every protein sequence and code for the methionine amino acid. UAG, UGA, and UAA are the stop codons if present at the end of the mRNA sequence and if any of these stop codons are present at the end of the sequence they do not produce any amino acid.

In this case, the mRNA sequence having 6 triplet codons AUG CCC UUU AUG GGG UAA where the first AUG is a start codon and code for the methionine and UAA is a stop codon and do not code for any amino acid therefore, the protein would carry only 5 amino acid and as there are two AUG so it has two methionine.

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