A blue-eyed myopic woman from a marriage with a brown-eyed man with normal vision gave birth to a brown- eyed myopic girl and a blue-eyed boy with normal vision. The gene for myopia (B) is dominant over the gene for
normal vision (c), and the gene for brown eyes (C) is dominant over the gene for blue eyes (c). What is the
probability of the birth in this family of a brown-eyed child with normal vision?
Выберите один ответ:
a. 50%
O b. 75%
c. 0%
O d. 25%​

option b 75%

Explanation:

this is the answer I guess

The answer is option B 75%

Explanation:

The probability of birth of a brown-eyed child with normal vision is 75%

thank you.

1. a host loses nutrients to a parasite

2. a parasite only benefits when the host is alive (cause if the host dies the parasite dies with it )

3. producers to consumers

4. the tapeworm is a parasite

5. they convert energy from the sun (photosynthesis)

6. sunflower-robin (i think im 80% sure)

7. producer

8. consumer

9. prey

10. fresh water snails ( cause the green algea is the producer and the snails are the primary consumers and the small fish consumer so is the big fish)