What is the initial velocity of the reaction catalyzed by the wild-type enzyme when the substrate concentration is 10 mM?

50 micro mol/min

Explanation:

So, we have the following parameters which are going to help us in solving this particular Question or problem;

=> For the wild type enzyme, the value for the Maximum velocity = 100 micromol/min.

=> For the mutant type enzyme, the value for the Maximum velocity = 1 micromol/min.

So, we can determine or calculate the value for the initial velocity for each of the enzyme type by using the formula below;

Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Therefore, for the wild type enzyme; the Initial velocity = (substrate concentration × maximum velocity) / substrate concentration + Km.

Initial velocity =( 10mM × 100micromol/min) ÷ ( 10mM + 10 mM ) = 50 micro mol/min.

Initial velocity for the wild type enzyme = 50 micro mol/min.

1) gene flow

- it is described as the transfer of genes from one population to another population so that frequency of gene is increased.

-a zebra migrates to join a different herd of zebras.

2) natural selection

- a mechanism of evolutionary change in which individuals with advantageous traits survive and reproduce whereas the others ( those that can not adapt) eliminate from the population.

-competition for sunlight leads to taller trees.

3) mutation

- permanent change in the nucleotide sequence of dna ( genetic material) that could have harmful or useful consequences.

-the dna of a snake changes to make its venom stronger.

4) genetic drift - it is a random phenomenon ( that occurs by chance such as fire) that results in change in the gene frequency in a small population.    

-a grassfire randomly sweeps through a population of buffalo and kills most of the animals.

explanation: