How much heat is needed to raise the temperature of 50.0g of water (4,182J/kgC) by 25.0C

Q = 5227.5 J

Explanation:

Given data:

Mass of water = 50.0 g

Temperature increase by = ΔT = 25°C

Specific heat capacity of water = 4182 J/Kg.°C

Heat required = ?

Solution:

(50.0 g×1 Kg/1000 g=0.05 Kg)

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = 0.05 Kg ×4182 J/Kg.°C ×  25°C

Q = 5227.5 J

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