PLEASE HELP QUICKLYYY We can also apply the equation for residence time to a single component of a fluid, such as carbon dioxide (CO2). Assume that the residence time of CO2 in the atmosphere is six years and the mass of CO2 in the atmosphere is 3 × 1015 kilograms. If these estimates are correct, what is the mass flow rate of CO2 into and out of the atmosphere? Assume the atmosphere is at steady state. Write your answer in scientific notation, and be sure to include the correct units.

Here is how you calculate  the mass of co2 in the atmosphere

5.100656e+14 m² * 1.02e+4 kg/m² = 5.202669e+18 kg

Explanation:

cells use diffusion to get substances in and out of themselves. that diffusion will occur across the cell membrane or the outer covering of the cell. because we are talking about the surface of the cell, surface area and volume are  important factors here. as a cell increases in size, its surface area and volume increase as well.  we call that the surface area to volume ratio (sa: vol).  but the catch is that  volume increases at a greater rate than surface  area. in other words, as a cell gets bigger, the sa: vol gets smaller. so a really small cell like bacteria is mostly cell membrane (surface) with very little contents (volume). a really big cell like an egg, is mostly insides with a super thin membrane. so what ends up happening is that the cell cannot efficiently diffuse all of the stuff it needs in/out to survive. therefore cell size is limited to about 100mm. so how do we make organisms bigger than 100mm? cells divide! by dividing and becoming multicellular, organisms are able to grow!   check out the diagrams i attached to see the effect of sa: vol. i hope this ! good luck!