When adding more sucrose to a 0.7 M sucrose solution, why does it not dissolve as readily as it did at a lower molarity? a) the ions in the solution interact with the sugar and that interferes with its solubility b) the solubility of the solute depends on wether the solute has hydroxyl functional groups or not c) the solute molecules adhere to the polar regions of the water molecules so there is no room for more sucrose molecules d) hydrogen bonds in the water molecules change the electrical charge of the sugar molecule, which prevents it from dissolving further in the water

The correct answer is option c.he solute molecules adhere to the polar regions of the water molecules so there is no room for more sucrose molecules

Explanation:

The Solution contains a solute (sucrose for this situation) and dissolvable (water for this situation). A saturation or unsaturation of a solution relying upon whether it can even now dissolve a solute or not.  

As indicated by this inquiry, the sucrose solution is saturated as the 0.7 M sucrose arrangement doesn't disintegrate the sucrose (solute) anymore. The immersion of the sucrose arrangement happens in light of the fact that the measure of solutes is likening the number of solvents in the solution. The solubility of a particular solution relies on saturation.

ionic bonds are two oppositely charged ions that attract. a sodium ion has a 1 positive charge; a chloride ion has a 1 negative charge. sodium and chloride have oppostive charged ions that attract which forms an ionic bond. a chemical bond formed when two atoms share electrons is called