If a purebred white horse C^w and purebred black horse C^B are bred together, what is the likehood that their offspring will roam with both colors represented? O 0%
O 25%
O 50%
0 100%

The likelihood that their offspring will roam with both colors represented is of 100%.

Explanation:

The exposed example brings up the case of a codominance example. When the hair color of horses is codominant, roan coats occur. Roan horses express both the colored and the whited hairs, with some of the animal´s parts expressing mostly the colored hairs, such as head, tail, and legs. These animals have white hair and another solid color (such as black). When two purebred animals with different genotypes and phenotypes are crossed, the whole offspring will be heterozygous.  In this case,  a purebred white horse C^w and purebred black horse C^B are bred together. The offspring will carry the heterozygous genotype C^wC^B. The offspring will have both red and white hairs.

In codominance, both alleles can be expressed. In these cases, heterozygote individuals instead of showing an intermediate phenotype, express both of the alleles (red and white hair). Their phenotype is an additive expression of their parents' genes.

Cross) purebred white horse C^w and purebred black horse C^B

Parental)  C^w C^w    x    C^BC^B

Gametes)C^w   C^w      C^B    C^B

F1) 100% roan animals, black and white.

     100% Heterozygous C^wC^B

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