Find the weight of a pine tree that has a circumference of 14 inches and a height of 120 feet. Use the equation: W = b0 + b1(D2H)

W = b0 + 2381 b1

Explanation:

First of all, you need to understand that in the formula shown above, the "W" represents the weight in tones. The "b0 + b1" are the constants, "D" is the diameter of the tree that must be presented in centimeters and the "H" is the height of the tree in feet.

As shown above, the circumference of the pine is 14 inches, but we know that the circumference is equal to 2πr, in this case, we will use the value 22/7.

I understand the factors above we will have the formula:

14 = 2 (7/22) × r

14 = (44/7) × r

r = 14 × 7/44 = 2.23 inches

So the diameter = 2r = 4.45 inches

Now we will replace the formula W = b0 + b1 (D2H).

W = b0 + b1 (4.45 ^ 2 * 120)

W = b0 + 2381 b1

To solve the rest we would need the values of b0 and b1, which we don't have. For that reason, the answer would be ended in this way.

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