A jar contains 5 brown marbles, 3 yellow marbles, 4 red marbles, 6 blue marbles, and 2 orange marbles. A marble is chosen and replaced. Then another marble is chosen. What is the likelihood that a brown marble AND a red marble were chosen?

1/20

Explanation:

Total number of marbles= 5 + 3 + 4 + 6 + 2 = 20

Probability of picking a brown marble P(Brown) = 5/20 = 1/4

Probability of picking a yellow marble P(Y) = 3/20

Probability of picking a blue marble P(B)= 6/20 = 3/10

Probability of picking an orange marble P(O)= 2/20= 1/10

Probability of picking a red marble P(R)= 4/20= 1/5

Since the marbles were chosen with replacement;

P(Br) and P(R) = 5/20 × 4/20 = 20/400= 2/40= 1/20

i think the answer would d

the endomembrane system i think