Assume there is a certain population of fish in a pond whose growth is described by the logistic equation. It is estimated that the carrying capacity for the pond is 1500 fish. Absent constraints, the population would grow by 170% per year. If the starting population is given by p0 = 400, then after one breeding season the population of the pond is given by p1 =.
After two breeding seasons the population of the pond is given by p2 =.

The population of fishes in the first generation will be 898 and in the second generation the population will be 1020.

Carrying Capacity:

It is the maximum number of individuals in a system at a certain time.

The logistic growth formula,

Where,  

r - rate of population increase = 1.7  

k- carrying capacity of the pond = 1500  

Po- initial population = 400

Put the values in the formula,

In second generation,

Po = 898,

So,

Therefore, the population of fishes in the first generation will be 898 and in the second generation the population will be 1020.

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The correct answer is  p1 = 898 and p2 = 1020.

Explanation:

This is a logistic growth problem and will utilize the following formula:  

Given ;

r = 1.7

k = 1500

Po = 400

then,

= 400 + 1.7 (293)

= 400+ 498

P₁= 898

Similarly,

=

= 1020

Thus, the correct answer is  p1 = 898 and p2 = 1020.

during the process of dna replication, brdu can replace thymidine and incorporate into the newly synthesized dna, cell proliferation thus can be reflected in the extent of brdu incorporation.

b is the correct answer