Biology, 05.07.2020 14:01 Qpaoswp5914

A dihybrid cross SS tt × ss TT is used to make an F1 generation. In the cross S is dominant, but T and t exhibit incomplete dominance. Assuming independent assortment, how many phenotypic classes are expected in F2 when crossing F1 individuals to each other?

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Answer from: jaylenmiller437

Explanation:

Given that:

A dihybrid cross SS tt × ss TT is used to make an F1 generation

where;

S = dominant

T and t exhibit incomplete dominance.

According to Mendelian's Law of Independent Assortment.

The cross between SS tt × ss TT will be as follows:

If self crossing occurs first, the following traits will be used for the F1 cross

S S

t St St

s s

T sT sT

St St St St

sT SstT SstT SstT SstT

Thus; the F1 generation produce offsprings that are all heterozygous SstT

For the F2 generation now;

We have

SsTt × SsTt

S s

T ST sT

t St st

ST St sT st

ST SSTT SSTt SsTT SstT

St SSTt SStt sSTt sStt

sT SsTT SstT sSTT sstT

st SsTt Sstt ssTt sstt

From the above F2 generation; we have the following offspring.

SSTT 3 = 3/16 = 0.1875 = 18.75 %

SStT 6 = 6/16 = 0.375 = 37.5%

Sstt 3 = 3/16 = 0.1875 = 18.75 %

ssTT 1 = 1/16 = 0.0625 = 6.25%

ssTt 2 = 2/16 = 0.125 = 12.5%

sstt 1 = 1/16 = 0.0625 = 6.25%

Answer from: Quest

True to the fact it is actually false

Answer from: Quest

21 stacks

step-by-step explanation:

divide 630/30

21 stacks

enjoy!

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A dihybrid cross SS tt × ss TT is used to make an F1 generation. In the cross S is dominant, but T a...