Researchers recorded that a certain bacteria population declined from 100,000 to 100 in 24 hours. At this rate of decay, how many bacteria would there have been at 16 hours from the start of the experiment? Use exact values in your calculations and do not round in intermediate steps. Your final answer should be a whole number ending in one or more zeros.

In 16 hours 66,667 number of bacteria were eliminated from the population of 100,000 bacteria.

Researchers recorded that a certain bacteria population decrease from 100,000 to 100 in 24 hours which means that in every hour 4167 number of bacteria were killed or eliminated.

If for one hour, 4167 number of bacteria were killed then in after 16 hours 66,667 number of bacteria were killed or eliminated from the population of 100,000 bacteria so we can conclude that in 16 hours 66,667 number of bacteria were eliminated from the population of 100,000 bacteria.

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A = 1013.25

Explanation:

First we will find the rate of decrease of population of bacteria

As we know that

Where A is the final population

the initial population

K is the rate of decrease of population

t is the time period

Substituting the given values, we get -

taking antilog on both sides, we get -

- 6.907 = k *24

k = -0.287 /hr

Now,

After 16 hour the population would be

complete the square on the right side of the equation;

-5(x + 0)^2 + 15

answer: d. y = -x^2 + 15

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