Sex-linked traits punnet squares - please help walk me through it! I’m so confused haha

Explanation:

a) The allele for hemophilia is Xh and that for normal is XH.

Crossing a hemophiliac male, Xh Y, with a normal female XH XH,

b) Both parents are normal and children still having hemophilia means that the mother is a carrier.

Let's see how it'll work out if we cross a normal male with a carrier female,

XH Y × XH Xh

This means that the possibility of a female being normal, a carrier or not, is 100%. The possibility of a male being normal is 50% and the possibility of him being a hemophiliac is also 50%.

Thus it's possible that all 7 sons get hemophilia as each male baby has a 50% chance of having the genotype Xh Y. And it makes sense that all the females are normal. Those females could have the genotypes XH XH, or XH Xh (carriers).

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if you know your abc's you should be able to get your answer or just use google