Asequence is defined recursively using the equation f(n + 1) = f(n) – 8. if f(1) = 100, what is f(6)?

F(1) = 100 
f(2) = 100 - 8 = 92 
f(3) = 92 - 8 = 84 
f(4) = 84 - 8 = 76 
f(5) = 76 - 8 = 68 
f(6) = 68 - 8 = 60 
 Arithmetic Serieshaving a1=100
 common difference d=-8
The nth term=a +(n - 1)d. 
When n = 6
 f(6) = 100 + (6 - 1)(-8)
 = 100 - 40
= 60.

The answer is c : ) hope this answered your question!