A female rabbit had eight babies. Six of the babies were black and two were white. In rabbits, the allele for black fur (B) is dominant to the allele for white fur (b). What genotype in the mother and father rabbits could produce this outcome in the phenotypes of their offspring? Write a scientific explanation that explains the genotype of the female and male rabbits.

Explanation:

You're told that solid-colored fur is dominant to spotted. That means that any rabbit that does have spots must have the ff genotype. The parent rabbits in this problem don't have spots, so they must either have the FF or the Ff genotype. But some of their babies do have spots -- some are ff. Every baby gets one copy of each gene from its mother and the other copy from its father. The spotted ff babies must have received one f allele from their mother, who must therefore be Ff, and one f allele from the father, who must also be Ff.

The dad is this case would either have a BB or a Bb genotype and the mother would have a bb genotype. Their babies that are white would be bb and black would be Bb. Every baby gets one gene from its mother and the another from its father. These white babies must have received one b allele from their mother and one b allele from the father and the black babies might have gotten a b allelle from the mom and a B from their father.

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