5. In humans, the gene for brown eyes is dominant over the gene for blue eyes. If two parents, both
heterozygous for brown eyes, have children, what is the probability of having a blue eyed child? In
addition, summarize all possible phenotypes and genotypes of this couple's offspring.

25%

Explanation:

Since both of the parents both have heterzygous for brown eyes, the first offspring would have homozygous brown eyes because the first B's of both parents meet up. The second child would be like the parents, heterozygous brown eyes (Bb), the third child (Bb), and finally the child with blue eyes for the fourth one since both of the parent's b's meet up (bb)

i'm gonna put a couple so you can chose from

explanation:

if you know the fur color of the offspring mice, you can use the ratios to identify the genotypes of the parents.

if either parent mouse passes a dominant allele, the offspring will have black fur.

if the parental mice has two different fur color (i.e white and black) , the color of the offspring's fur would be either black, white, or the combination of both (grey)

hope this : )

this would be a math