A gas has an initial volume of 2.4L at a pressure of 1.5 atm and a temperature 273K. The Pressure of the gas increases to 4.5 atm, and the temperature of the gas increases to 313k. What is the final volume of the gas

The answer to your question is  V2 = 0.92 l

Explanation:

Data

Volume 1 = V1 = 2.4 l

Pressure 1 = P1 = 1.5 atm

Temperature 1 = T1 = 273 °C

Volume 2 = V2 = ?

Pressure 2 = 4.5 atm

Temperature 2 = 313 °K

Process

To solve this problem use the Combined gas law

                     P1V1/T1 = P2V2/T2

-Solve for V2

                     V2 = P1V1T2 / T1P2

-Substitution

                     V2 = (1.5 x 2.4 x 313) / (273 x 4.5)

-Simplification

                     V2 = 1126.8 / 1228.5

-Result

                     V2 = 0.92 l

the answer

b.) bowling ball