In one type of dog, black spots (b) are dominant over brown spots (b) and long tails (l) are dominant over short tails (l). complete a dihybrid cross for parents with the genotypes: bbll × bbll and answer the following in complete sentences.

describe how you would set up a punnett square for this cross.
list the likelihood of each possible offspring genotype.
list the likelihood of each possible offspring phenotype.

Genotypes of offspring will be BBLL, BbLL, BBLl, and BbLl.

The phenotype of offspring will be all black spots with long tails.

Explanation:

A cross between BbLL and BBLl will form BL, bL, and Bl, BL gametes respectively. All gametes will assort independently and produce offspring of with different genotypes,

The genotype of possible offsprings will be - 25% BBLL (black spot dog with long tail), 25% BbLL (Black spot dog with long tail), 25% BBLl (black spot dog with long tail) and 25% BbLl (black spot dog with long tail)

The phenotype of possible offsprings will be - 100% black spot dog with long tail because there always a copy of dominant alleles are present in the genotype of each offspring.

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the corpus luteum secretes estrogens and progesterone. the latter hormone causes changes in the uterus that make it more suitable for implantation of the fertilized ovum and the nourishment of the embryo. if the egg is not fertilized, the corpus luteum becomes inactive after 10–14 days, and menstruation occurs.

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