Apopulation of mice has black or brown hair. the gene for black hair color (b) is dominant over brown (b). if 16% of the mice are homozygous black and 24% are heterozygous black, what would be the frequency of each allele? . (p + q = 1, p2 + 2pq + q2 = 1). is it (a. p=0.65, q=0.35 (b. p=0.25, q=0.75 (c. p=0.4, q=0.6

Frequency of black allele is

Frequency of brown allele is

Explanation:

As per Hardy-Weinberg equation,

Frequency of the homozygous genotype is represented by AA and aa

Frequency of the heterozygous genotype is represented by Aa

In the  Hardy-Weinberg mathematical equation

Frequency of AA is represented by

Frequency of AA is represented by

Frequency of AA is represented by

And the mathematical equation is as follows -

Substituting the given values in above equation we get

Also,  sum of the allele frequencies for all the alleles at the locus is equal to  1 which means

Frequency of black allele is

Frequency of brown allele is

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explanation: