Use the information from Parts B and C to solve this problem. If a rabbit of genotype AaBb is bred to a rabbit of genotype AaBb, what is the probability of producing an offspring with an ear length of 13.5 cm? Enter your answer to two decimal places. (example: 0.45) nothing

The question is incomplete and the complete question is

Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.

AABb or AaBB

Explanation:

We know that,

aabb genotype - 6 cm

AABB genotype- 16-cm

To calculate the length of earlobe contributed by each allele in a genotype is :

1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)

2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)

Now to have the earlobe to be 13.5 cm long then the genotype must be

13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B

Therefore, the genotype will be-either AABb or AaBB

answer; i believe the correct answer is (a)0

ι вєℓινє тнє αиѕωєя тσ уσυя qυєѕтισи ιѕ в. ℓуѕσѕσмє

ι нσρє тнαт ι ¢συℓ∂ нєℓρ уσυ.