Abody was found at 10 a. m. outdoors on a day when the temperature was 40of. the medical examiner found the temperature of the body to be 80of. what was the approximate time of death? use newton's law of cooling, with k = 0.1947.

8 am

Explanation:

Equation of newtons law of cooling is  -

Where is ambient temperature which is equal to

80 degree Fahrenheit

degree Fahrenheit

Substituting the given values in above equation we get -

Taking log on both sides we get -

hour

which is almost 2 hour

So the time of death would be two hour before 10 am

i.e 8 am

idk let me see fdfdgdg

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