DNA sequencing of an E. coli colony isolated from a nozzle that had biofilm growth of both bacteria shows that conjugation has occurred. However, the transformed strain of E. coli did not express any new proteins. BLAST analysis shows that the gene for the L. monocytogenesprotein is incomplete in E. coli. Sequence comparison shows that E. coli has a truncated version of the gene that begins at nucleotide number 54 and continues to nucleotide 1257, meaning that no start codon is present.
Why would this interfere with transcription or translation?
1.DNA bases are species specific
2. no start codon for translation
3. E. coli DNA polymerase does not recognize an L. monocytogenes gene sequence
4. no promoter region for the transcription to begin at.

Explanation:

Translation starts when translation machinery encounter  start codon( AUG) in mRNA. tRNA brings amino acids for protein synthesis according the sequence of nucleotide in mRNA, and protein synthesis occurs with the help of ribosomes. If the gene is truncated or their sequence is so changed that there is no start codon, then the translation will never happen.

In this case in E. coli ; sequence comparison result  shows that E. coli has a truncated version of gene, means mutated type  of the gene that begins at nucleotide number 54 and continues to nucleotide 1257, meaning that there is  no start codon is present. So when there is no codon  codon then there is no translation, so it interfere with translation.

answer; i believe that the correct answer is(d) nondisjunction during meiosis;

can you give me more to work here with plzs and you