16. The presence of freckles (F) is dominant to the absence of freckles (f). Using Punnett squares, determine the phenotypic and genotypic ratios that you would expect from the following crosses: a. Parent 1: Homozygous dominant Parent 2: Homozygous recessive b. Parent 1: Heterozygous Parent 2: Homozygous recessive c. Parent 1: Homozygous recessive Parent 2: Homozygous recessive d. Parent 1: Heterozygous Parent 2: Heterozygous

There is no short answer.

Explanation:

The genotypes for the two parents in option A are FF and ff, so the resulting phenotypic and genotypic ratios that would be 100% absence of freckles and 100% Ff respectively.

The genotypes for the two parents in option B are Ff and ff, so the resulting phenotypic and genotypic ratios that would be 100% absence of freckles and 50% Ff, 50% ff respectively.

The genotypes for the two parents in option C are ff and ff, so the resulting phenotypic and genotypic ratios that would be 100% absence of freckles and 100% ff respectively.

The genotypes for the two parents in option D are Ff and Ff, so the resulting phenotypic and genotypic ratios that would be 75% absence of freckles, 25% freckles and 50% Ff, 25% FF, 25% ff respectively.

I hope this answer helps.