If one strand of a DNA molecule has the sequence of bases 5-ATTGCA-3, the mRNA synthesized following the template will be . If one strand of a DNA molecule has the sequence of bases 5-ATTGCA-3, the mRNA synthesized following the template will be . 5-TGCAAT-3 5-UGCAAU-3 5-TAACGT-3 3-UAACGU-5

5-UGCAAU-3

Explanation:

During a process called transcription, DNA is transcribed into messenger RNA (mRNA) and then translated to make proteins.

DNA contains the nucleotide bases: Adenine (A), Thymine (T), Guanine (G) and Cytosine (C). DNA is double stranded and the strands are complementary. The bases on one strand are bound to the bases on the other. As such, A binds to T and C bind to G.

RNA contains the nucleotide bases: Adenine (A), Uracil (U), Guanine (G) and Cytosine (C).

Thymine in DNA is replaced by Uracil in RNA

During transcription, the complementary DNA base is synthesized to RNA. For instance A is transcribed to U, T to A, G to C and C to G.

Since there are two DNA strands, one strand is in the direction 5' to 3' while the other is in the opposite direction, 3' to 5'. However, the direction of transcription is from the 3' to the 5' end, so the 3' to 5' end is what serves as the template to make RNA.

[DNA 5' to 3' strand is called coding strand, while 3' to 5' strand is called template strand]

Assuming 5-ATTGCA-3 is the template strand, let's rewrite it in reverse to be 3-ACGTTA-5.

The complementary RNA equivalent is UGCAAU

(Recall that DNA bases are complementary and they bind in a particular format).

Although the RNA is made from a 3' to 5' direction of DNA, the resulting RNA is 5' to 3'

Hence, the answer is 5-UGCAAU-3

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