Biology, 10.03.2020 03:02 lokiliddel
A fruit fly of genotype a+/a . b+/b (parent 1) is crossed to another fruit fly of genotype a/a . b/b (parent 2). The progeny of this cross were: Genotype / Number of individuals a+/a . b+/b / 15 a/a . b/b / 12 a+/a . b/b / 34 a/a . b+/b / 39 The original arrangement of alleles in parent 1 would have been what?
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A fruit fly of genotype a+/a . b+/b (parent 1) is crossed to another fruit fly of genotype a/a . b/b...
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