A corn plant known to be heterozygous at three loci is testcrossed. The progeny phenotypes and numbers are as follows:+ + + 455a b c 470+ b c 35a + + 33+ + c 37a b + 35+ b + 460a + c 475Total 2,000Give the gene arrangement, linkage relationships, and map distances.

The progeny phenotypes and numbers are as follows:

+ + + 455 parental

a b c 470 parental

+ b c 35 recombinant

a + + 33 recombinant

+ + c 37 recombinant

a b + 35 recombinant

+ b + 460 parental

a + c 475 parental

Total 2,000

+ + + 455 parental

a b c 470 parental

+ b + 460 parental

a + c 475 parental

It is two point testcross

So the parental ++ (455+460); ac (470+475)++/ac

Gene order is ++/ac

+ b c 35 recombinant

a + + 33 recombinant

+ + c 37 recombinant

a b + 35 recombinant

sum of recombinants140

Frequency of recombintion= recombinants/total x100

Map distances between a-c = (140/2000) x 100 = 7 mu

a7 mu c

Explanation:

interphase   is the cell cycle stage in which the cell acquires nutrients, creates and uses proteins and other molecules and starts the process of cell division by replicating the dna. it is the longest stage in the eukaryote cell cycle.

the following   can go wrong during interphase:   a base pair could be mismatched during the duplication process causing a mutation.   correct answer: c

explanation: