Referring to the triplicate Bradford data for the E3 fraction, what sample volumes did you use in the assays and what microplate absorbance values did you record?Show how you calculated the total amount of protein and the standard deviation for the E3 fraction that you plotted on your "combined elution/activity profile."

Please give a detailed answer

Answer is explained below:

Explanation:

There are 12 fractions performed in triplicate Bradford data.1 ml of Bradford reagent and 50μl of protein is taken and mixed in a test tube for total volume of 1.05ml.The value taken of Bradford assays by microplate agent are compared through standard curve. This standard curve is made by using specific amounts of protein within each Bradford and then calculated by linear equation of standard curve.

Linear equation for standard curve is Y=0.0245 x + 0.03605

For the 1st trial of E3 :

it can be written as 0.511 = 0.0245 x + 0.3605 + x→  = 6.14μg

For the 2nd trial of E3 :

it can be written as 0.489 = 0.0245 x + 0.3605 + x→  = 5.24μg

For the 3rd trial of E3 :

it can be written as 0.478 = 0.0245 x + 0.3605 + x→  = 4.80μg

standard derivation = √∑ | x - average|²

                                                    n-1

by putting values in derivation, we will get 0.683

and

Standard derivation = √?

answer: accepted answer: aquatic animals use the oxygen dissolved in water to carry out respiration. since the amount of dissolved oxygen in water is low as compared to the amount of oxygen in the air, therefore the rate of breathing in aquatic animals is much faster than it is in terrestrial animals.

explanation:

as in mitosis, dna replication occurs during interphase.   in meiosis, it occurs specifically in s phase of interphase 1.