A long-winged Drosophila female with a gray body mates with a black, short-winged male fly. The phenotypic ratio of the offspring is 1:1:1:1. What is the genotype of the female fly?

Explanation:

To obtain a phenotypic ration of 1:1:1:1 one of the parent must be heterozygous for both the trait and other parent must be homozygous recessive for both the trait.

If the long winged Drosophila with gray body is dominant then, it is represented by these genotype- LLGG, LlGG, LlGg and LLGg. Short and black Drosophila is considered as recessive (llgg)

Different crosses were carried to obtain a phenotypic ratio of 1:1:1:1.

So, if we cross LlGg with llgg we obtain a phenotypic ratio of 1:1:1:1

we obtain Drosophila which are

Long gray (4)

Long black (4)

Short gray (4)

Short black (4)

So, ratio comes out to be 1:1:1:1

on the planet jupiter, the acceleration due to gravity is approximately 26 m s2 , roughly 2.7 times the acceleration due

the level of progesterone is low at the pre-ovulatory phase of the cycle but it gradually increases and the levels are high at the luteal phase. if pregnancy occurs, the level of progesterone will be high throughout the pregnancy.

if egg is fertilized and the mother gets pregnant, progesterone starts preparing the uterus for the implantation. it starts building up the lining of uterus and make it hostile of the period of pregnancy.