What is the expected Hardy-Weinberg frequency of heterozygotes in a population of green anoles, where the locus under investigation has two alleles and the frequency of one allele is 0.005 (give your answer to five decimal places)

0.00995

Explanation: The Hardy-Weinberg

theorem states that:

1. allele frequencies in a population will not change from generation to generation.

2. if the allele frequencies in a population with two alleles at a locus are p and q, then the expected genotype frequencies are P², 2pq, and q². For a population in genetic equilibrium:

p + q = 1.0

Where

p = the frequency of the dominant allele

q = the frequency of the recessive allele

Therefore

p² + 2pq + q² = 1

Where

p² = frequency of AA (homozygous dominant)

2pq = frequency of Aa (heterozygous)

q² = frequency of aa (homozygous recessive)

To get the frequency of frequency of heterozygotes in a population of green anoles,

p + q = 1.0

P= 0.005

q= ?

Therefore

q= 1 - P

q= 1 - 0.005

q= 0.995.

Therefore, the frequency of heterozygotes in a population of green anoles is 2Pa

Where P = 0.005

q= 0.99

Frequency of heterozygotes is

2Pa= 2 x 0.005 x 0.995

= 0.00995(five decimal)

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