A black-eyed cat mates with an orange-eyed cat and produce all offspring with black eyes. Assuming these genes follow mendelian genetics, what is the expected phenotypic ratio of a cross between two orange-eyed cats?

all orange eyed

Explanation:

Mendelian genetics operate on the laws of segregation and independent assortment. This means that genes  from either parent segregates independently and are separated into gametes at an equal frequency.

Since a cross between all the black-eyed cats and orange eyed cats lead to all black eyed cats. It is safe to assume that the black eye phenotype is dominant and the orange eye phenotype is recessive. If two orange eyed cat crossed then all the offspring would be orange eyed.

answer : haversian

[explanation: -(compact bone is organized as parallel columns, known as haversian systems, which run lengthwise down the axis of long bones. these columns are composed of lamellae, concentric rings of bone, surrounding a central channel, or haversian canal, that contains the nerves, blood vessels, and lymphatic system of the bone)]