I need some help
In one type of dog, black spots (B) are dominant over brown spots (b) and long tails (L) are dominant over short tails (l). Use the dihybrid cross for parents with the genotypes BBLl and BbLl and determine the likelihood of offspring with the phenotype of brown spots and short tails. BL Bl BL Bl BL BBLL BBLl BBLL BBLl Bl BBLl BBll BBLl BBll bL BbLL BbLl BbLL BbLl bl BbLl Bbll BbLl Bbll 0% 10% 20% 50%

0%

Explanation:

It was a little hard to see your cross, so I made another one and it is attached below.

So what you are looking for is the likelihood of an offspring with a phenotype of brown spots and short tails.

Without using the Punnet, we can already deduce that it is 0%. This is because brown spots are recessive, and the only way a brown spotted dog would have this trait, is each parent had at least 1 recessive allele for this trait.

So the expected genotype for brown spot would be:

bb

Only one of them has this, so they cannot have brown spots.

thrombocytopenia, which is a deficiency in blood platelets, can cause bleeding and bruising in the dermis similar to senile purpura. other possible causes include: exposure to ultraviolet rays and aging skin are common causes of senile purpura. senile purpura may also be a sign of collagen loss in the skin and bones.

the actual answer was 160934