A population has a gene locus with two alleles, A1 and A2. Tests show that 30% of the gametes produced in the population contain the A1 allele. If the population is in Hardy-Weinberg equilibrium, what proportion of the flies carry both A1 and A2?

The question is incomplete as it does not have the options which are:

0.42

Explanation:

Hardy Weinberg equilibrium states that a population doe not evolve if no evolutionary force act on the population as the population remains in equilibrium.

The principles considered dominant allele as P and recessive allele as q. The sum of allele frequency will be p+q = 1 and the genotypic frequency will be P²+2Pq+q²=1.

2pq represents the population which is heterozygous that is having both the alleles.

In the given question, since the allele frequency of A1 is 30% or O.30, Therefore using p+q=1,   the frequency of A2 allele will be 1-p= 0.70.

Now 2pq will be 2x (0.30 x 0.70)

= 2x .210

=. 420

Thus, 0.42 is the correct answer.

yes!

explanation:

because it has a type of fat that can make you extremely sick

the alkaline earth metals (beryllium (be), magnesium (mg), calcium (ca), strontium (sr), barium (ba), and radium (ra)) are a group of chemical elements in the s-block of the periodic table with very similar properties: shiny. silvery-white. hopefully this ? i didn't fully understand the question