Two genes, A and B, are located 30 map units apart. A mating between an individual homozygous dominant for both traits and one homozygous recessive for both traits is conducted. The F1 progeny is then test-crossed to a homozygous recessive individual. What proportion of their offspring is expected to be dominant for both traits?

35%

Explanation:

If two genes are 30 map units apart, 30% of the produced gametes will be recombinant.

A mating between an individual homozygous dominant for both traits (AB/AB) and one homozygous recessive for both traits (ab/ab) is conducted.

The F1 will be heterozygous for both genes: AB/ab.

The F1 progeny is then test-crossed to a homozygous recessive individual:

The possible offspring will be:

Since 30% of all the gametes produced by the F1 individual will be recombinant, 70% will be parental. As there are two types of parental gametes, each of them will have a frequency of 35%.

The offspring that will have a dominant phenotype for both traits has the genotype AB/ab with a proportion of 35%.

one is through turgidity. this occurs before ground tissue ( collenchyma

and sclerenchyma cells) become well

developed to give structural support to the plant as it grows bigger. the xylem

tissue (composed of rigid tissue) of the young

plant render this support and also maintaining osmotic turgidity of the surrounding

plant cells.

it takes hundreds of years to become stable.

if you have another question lmk.