A 1475 kg car with a speed of 66.5 km/h brakes to a stop. How many cal of heat are generated by the brakes as a result?

Explanation:

Let's start by stating that the work done here would be determined by taking into account the following:

-External forces

-Change in kinetic energy

Work Energy theorem is fully going to guide the solution to this problem.

Let's go now:

Mass of car = 1475kg

Velocity of car= 66.5km/h

Velocity = 66.5km/h * 0.278

V = 18.472 m/s

Kinetic Energy (K.E) = 1/2(mv^2)

K.E = 0.5 * 1475 * 18.472^2

K.E = 737.5 * 341.214

K.E = 251645.90 kgm^2/s^2

1kgm^2/s^2 = 1 Joule

So therefore,

K.E = 251645.90 Joules

K.E = 60.144KCals

the diploid number of chromosomes is sometimes represented by the symbol 2n. for the fruit fly, the diploid number is 8, which can be written as 2n = 8, where n represents twice the number of chromosomes in a sperm or egg cell.

easy

explanation: