Consider this mating between genotypes AaBBccDd and AabbCCDd, where A, B, C and D are loci that assort independently and the uppercase and lower case letter indicate the dominant allele and recessive allele respectively. a. What is the probability that any given offspring of this pair will be heterozygous at all loci?b. What is the probability that an offspring will be homozygous at all four loci?c. What is the probability that an offspring will be phenotypically dominant?

Explanation:

AaBBccDd x AabbCCDDd ---Parents

Aa x Aa = AA (1/4), Aa (1/2) & aa (1/4)

BB x bb = Bb (1)

cc x CC = Cc (1)

Dd x Dd = DD (1/4), Dd (1/2), dd (1/4)

a). The probability that any given offspring of this pair will be heterozygous at all loci = AaBbCcDd = ½ * 1*1*1/2 = ¼

b). The probability that an offspring will be homozygous at all four loci =AABBCCDD = ¼*0*0*1/4 = 0

c). The probability that an offspring will be phenotypically dominant = A_B_C_D_ = ¾ * 1 * 1* ¾ = 9/16

try using substitution:

x + y - 6 = x - y. (i'm not giving you the exact answer). since 0 = x - y, then sub 0 in the equation with x - y. combine your like terms, and then use inverse operations, and you'll have your answer.

: -)

what are the options