If flower position (axial or terminal) is inherited as it is in pease what will be the ratios of genotypes and phenotypes in the f1 generation resulting from the following cross axial red x terminal white?

Genotype ratio: 100% AaRr

Phenotype ratio: 100% axial and pink flowers

Explanation:

This is the complete question:  In some plants, a true-breeding, red-flowered strain gives all pink flowers when crossed with a white-flowered strain: RR (red) x rr (white) —> Rr (pink). If flower position (axial or terminal) is inherited as it is in pease what will be the ratios of genotypes and phenotypes in the F1 generation resulting from the following cross axial red x terminal white?

Let flower position allele be A.

Genotype of a true breeding axial red = AARR

Genotype of a true breeding terminal white = aarr

Crossing    AARR  x  aarr

All the progeny will have genotype AaRr

Since the flower position gene segregates according to Mendelian law (as seen in peas), A is dominant over a. However R exhibits incomplete dominance over r to give a pink colour.

Hence, the phenotype of the progeny will be axial flower position and pink flower color.

yes i have all the correct answers

1. c 6. b. 11. c

2. a 7. d. 12. d

3. c 8. b. 13. c

4. d 9. c. 14. d

5. c 10. d. 15. a

16. d. 21. a

17. d.

18. a. 22-30 you must do on

19. d. your own

20. d.

the offspring would all be white. if the parents are both white flowers then they have the genotype rr, which when crossed results in an all white punnet square.