Assume that the a and b loci are linked and separated by a distance of 20 map units on a chromosome (i. e., 20% recombination occurs between the two loci). a p0 cross is aabb x aabb. the f1 resulting from this cross is aabb. if you cross this f1 "dihybrid" to an individual with genotype aabb, what frequencies of genotypes do you expect in the following generation? (hint: the p0 generation tells you how the alleles are linked.)

The frequencies would be - AaBb= 2/4= 1/2 Therefore AaBb= 50%

                                              - aabb=  2/4= 1/2 Therefore aabb= 50%

Explanation:

The resulting F1 cross, AaBb, indicated that A is dominant over a, and B is dominant over b. Therefore a cross between AaBb and aabb would result to---

                                 AaBb                x               aabb

                     =       AaBb         AaBb       aabb        aabb

question: which statement best describes the different properties of metals?

answer: they are shiny and bend without breaking.

since metals have certain characteristics properties, they include the following: they are ductile, malleable, shiny, hard, lustrous, flexible and they are good conductor of heat and electricity. so therefore, metals are not dull and they are not non-flexible as listed. instead, they are shiny and flexible.

hope this , have a good day. c;