Question 5: the human genome contains about 3 billion base pairs. during the first cell division after fertilization of a human embryo, s phase is approximately three hours long. assuming an average dna polymerase rate of 50 nucleotides/second over the entire s phase, what is the minimum number of origins of replication you would expect to find in the human genome

5556.

Explanation:

By the orientation of this question, we will not take in account the information in literature that states that human genome has tens of thousands origin of replication.

Simple math: 3 hours equals 180 minutes, 10800 seconds. Assuming a DNA pol rate of 50 nucleotides/second, we are talking about 540000 nucleotides by every origin of replication on the S phase time.

If the homan genome is about 3 billion base pairs long, 3,000,000/540000= 5555.55, and goes round up to 5556 for the matter of this question.

hydroxyl -oh

alcohols, always polar, can form hydrogen bonds with h2o molecules

carboxyl -cooh  

cargoxylic acids, has acidic properties which is a source of hydrogen ions, found in cells in ionized for with a charge of oh-1

carbonyl > co

ketone if within skeleton, aldehyde if group is at the end of skeleton, k & a may be structural isomers, it determines 2 sugars (ketose & aldose)

amino -nh2

amines, acts as a base, it can pick up h+ ions from surrounding solution, ionized with charge of 1+

methyl ch2

addition to rna/dna affects and gene expression

phosphate -opo3 ²⁻

organic phosphates, contributes to negative charge to, molecule that it is a part of, and potential to react with h20

sulfhydryl -sh

thiols, cross-linking stabilize the protein, and it is structure

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explanation:

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