The genetic frequencies of two separate populations are: aa - aa - aa population 1: .36 - .48 - .16 population 2: .55 - .10 - .35 a) what are the genotypic frequencies of the two populations? b) what are the allele frequencies? c) are the populations in hardy-weinberg equilibrium?

Explanation:

Population 1

AA Aa aa Total

36 48 16 100

Gene frequency 0.36 0.48 0.16

Allele frequency

A = 0.36 + (0.50×0.48) = 0.60

A = (0.48×0.50) + 0.16 = 0.40

Population 2

AA Aa aa Total

55 10 35 100

Gene frequency 0.55 0.10 0.35

Allele frequency

A = 0.55 + (0.50×0.10) = 0.60

A = (0.10×0.50) + 0.35 = 0.40

Note. Formula for gene frequency = no of genotype/total population

The populations are not in Hardy-Weinberg equilibrium. This is because Hardy-Weinberg equilibrium states that the variation in a population will remain constant from one generation to the next in the absence of disturbing factors. However, the data for this calculation is from two different populations and there is do predating data of each population to know if the genetic variations has remained the same with the previous population.

littering streams           is the answer

not sure but try c two haploid cells

explanation: