Andalusian chickens exhibit incomplete dominance and they can have black feathers (bb), white feathers (bb) or gray feathers (bb). what would the phenotypes of the offspring be if you mated a heterozygous male with a heterozygous female?
group of answer choices

75% black feathers, 25% white feathers

25% black feathers, 50% gray feathers, 25% white feathers

100% black feathers

50% black feathers, 50% gray feathers

The second answer is correct.

If we make a punnet square: (sry if its weird, i had to improvise, lol)

       B           b     -

__---

B  -  BB   -   Bb    -

__---

b  -  Bb    -  bb     -

We know that both the female and male are heterozygous, meaning the alleles are different, so one would be dominant, and one would be recessive( for both the female and male). So both female and male would be Bb, as on the punnet square. If we cross them, we get BB, Bb, Bb, and bb. So, 25% of that is BB, which is black feathers. We have 50% of gray feathers, Bb, and 25% white feathers, bb. Therefore, the second option is correct.