Suppose that we are dealing with four genes, each gene consisting of a dominant allele (capital letter) and a recessive allele (small case letter). if the cross ccmmllpp x ccmmllpp is made, what is the probability of obtaining an individual who is ccmmllpp?

1/16

Explanation:

The desired genotype is "CcmmLLPp". The proportion of the desired genotype can be calculated by using the product rule. The probability of getting Cc, mm, LL and Pp genotype can be calculated separately first and then the product rule is applied.  

Parents= CcMmLlPP X CCmmLlpp

Cc x CC= 1/2 Cc: 1/2 CC

Mm x mm= 1/2 Mm: 1/2 mm

Ll x Ll = 1/4 LL: 1/2 Ll: 1.4 ll

PP x pp= All Pp

Therefore, the probability of obtaining an individual who is CcmmLLPp = 1/2 Cc x 1/2 mm x 1/4 LL x 1 Pp = 1/2 x 1/2 x 1/4 =1/16

a motor homunculus represents a map of brain areas dedicated to motor processing for different anatomical divisions of the body.

homunculus represents the importance of various parts of your body as seen by your brain. as a result, they take up a lot of brain space. although the cortical homunculus is a curiosity, penfield's work in mapping the brain's relationship to the body was invaluable.

chert is a sedimentary rock composed of microcrystalline or cryptocrystalline silica. with this little bit of information, you can come to the conclusion that your answer is c.  

explanation: