In peas, axial (a) flower position is dominant to terminal (a), tall (l) is dominant to short (l), and yellow (y) is dominant to green (y). if a plant that is heterozygous for all three traits is allowed to self-fertilize, how many of the offspring would be dominant for all three traits? in peas, axial (a) flower position is dominant to terminal (a), tall (l) is dominant to short (l), and yellow (y) is dominant to green (y). if a plant that is heterozygous for all three traits is allowed to self-fertilize, how many of the offspring would be dominant for all three traits? 3/64 32/64 27/64 64/64 9/64

27/64

Explanation:

Axial flowers (A) are dominant to terminal (a)Tall (L) is dominant to short (l)Yellow (Y) is dominant to green (y)

The genotype of the heterozygous plant can be written as AaLlYy and the cross would be AaLlYy x AaLlYy.

If the three genes are independent, we can analyze each gene individually, obtain the proportion of offpsring with the dominant allele for each gene, and then multiply those probabilities to obtain the probability of having A_L_Y_ offspring, because the rules of probability state that the probability of two independent events occurring at the same time can be calculated as the multiplication of the probabilities of occurrence of each event.

Aa x Aa

3/4 A_1/4 aa

Ll x Ll

3/4 L_1/4 ll

Yy x Yy

3/4 Y_1/4 yy

So the total proportion of offspring with dominant phenotype for all traits will be 3/4 × 3/4 × 3/4 = 27/64

Mitochondria is the cell organelle that produced the energy that is needed in the body system in form of atp, that is why it is called the power house of the cell. energy is needed by the living organisms to carry out the activities which sustain life.  if the mitochondria is destroyed atp will not be produced. if the mitochondria is destroyed, energy production will stop and the affected living organism will not have the energy to carry out the necessary life processes; this will lead to the death of the organism.

Ithink the answer is d.