Which of the following is the most accurate comparison of the two yeast samples studied in the microarray analysis at the time of sporulation?
a) the number of different genes expressed in sporulating yeast is likely to be greater than the number of different genes expressed in nonsporulating yeast.
b) the two yeast samples share a common genome, but display differences in their transcriptomes.
c) the two yeast samples share a common transcriptome, but display differences in their genomes.
d) cdnas from sporulating yeast were applied to a microarray spotted with cy-5–labeled gene segments.
e) cdnas from nonsporulating yeast were applied to a microarray spotted with cy-3–labeled gene segments.

it is a limiting nutrient limited by a single nutrient in the ecosystem, & the single goes very slow.

we solve the problem using the hardy-wineberg equation.

let us start with the homozygous recessive proportion of individuals with sickle cell anaemia,

we have the proportion as q² = 0.25.

∴ q = 0.5 (frequency of hbs in population)

further,

solving for the frequency of normal cell by using the fact that,

p + q = 1

∴ p = 1 - 0.5 = 1 - 0.5 = 0.5

now we can calculate 2pq in p² + 2pq + q², which is the frequency for heterozygous carriers of sickle cell anaemia,

∴ 2pq = 2 x 0.5 x 0.5 = 0.5

and the homozygous normal cell individuals proportion is given by the expression,

∴ p² = 0.5² = 0.25

hence, the carriers for sickle cell anaemia are in proportion, 0.5, or 50%.