In fenzars, the genes for twisted horns (t) and purple lips (p) are 12 map units apart. phenotypically wild-type females (t+p / tp+) were mated to twisted-horned males with purple lips. what percent of offspring would you expect to have twisted horns and wild type lips? group of answer choices

44%

Explanation:

Parent 1 : wild type = t+p/tp+

Parent 2: recessive type = tp/tp

If t and p genes are 12 map units apart that means that they are linked genes and can have 12% recombinants. Parental type offspring would be 88%. Here parental gametes from parent 1 are t+p and tp+.

When tp+ gametes combine with tp gametes from parent 2 we will get the genotype tp+/tp which will result in twisted horns and wild type lips. Out of the total 88% parental type offspring, this genotype would be 44% since t+p/tp will make rest 44% offspring genotype.

Hence, 44% offspring would have twisted horns and wild type lips.

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