Assume a population is in hardy-weinberg equilibrium for the b gene, which has two alleles, b and b. in this population of 100,000 individuals, if the frequency of the b allele (q) is 4%, how many homozygous bb individuals would you expect to find in the population?

160

Explanation:

If p = frequency of dominant allele and q = frequency of recessive allele according to Hardy-Weinberg equilibrium,

p + q = 1

p² + 2pq + q² = 1

where p² = frequency of dominant homozygous genotype

q² = frequency of recessive homozygous genotype

2pq = frequency of heterozygous genotype

Here,

b = 4% = 0.04

bb = 0.04 * 0.04 = 0.0016

Number of individuals in population = 100000

Number of homozygous bb individuals = 0.0016 * 100000 = 160

they each offer a fresh glut of resources to the organisms that can arrive and exploit them. as individuals and new species continue to appear, they actively and passively alter the environment. competition for shared resources increases, local abiotic and biotic conditions shift, and the relative abundances of species change accordingly. the process is called ecological succession, and it is one of the earliest and most well-known concepts in ecology.

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