Aman has six fingers on each hand and six toes on each foot. his wife and their daughter have the normal number of digits. remember that extra digits is a dominant trait. what fraction of this couple’s children would be expected to have extra digits?

1/2 or 50%

Explanation:

Given that the extra digit is a dominant trait, the man with an extra digit may be homozygous or heterozygous dominant for the trait.

However, having a daughter with his normal wife makes him heterozygous dominant. Let's assume that the genotype of the heterozygous dominant male is "Dd" and that of his wife is "dd".

The heterozygous dominant male and homozygous recessive female would have progeny in the following ratio= 1/2 Dd (child with extra digit): 1/2 dd (child with no extra digit).

i think the answer would d

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