What is the probability that each of the following pairs of parents will produce the indicated offspring? (assume independent assortment of all gene pairs)
a. aabbcc x aabbcc > aabbcc
b. aabbcc x aabbcc > aabbcc
c. aabbcc x aabbcc > aabbcc
d. aabbcc x aabbcc > aabbcc
e. aabbcc x aabbcc > aabbcc

The only way to know the possibilities of the offspring is to draw the Punnett squares (photos).

On each allele space, you put one of each characteristic, and then you cross the three of them at the same time.

You will found the four possibilities of those crossings.

a. AABBCC X aabbcc =AaBbCc, AaBbCc, AaBbCc, and AaBbCc

So, you have 100% of the offspring AaBbCc

b. AaBbCc X AaBbCc = AABBCC, AaBbCc, AaBbCC, aabbcc

So, you have a 25% chance of having AABBCC offspring.

c. AABbCc X AaBbCc= AABBCC, AaBbCc, AABbCc, and Aabbcc

So, none of the offspring could be AAbbCC

d. AaBbCc X AaBbCc=AABBCC, AaBbCc, AaBbCc, and aabbcc

So, you have a 50% chance of having AaBbCc offspring.

e. aaBbCC X AABbcc=AaBBCc, AaBbCc, AaBbCc, and AabbCc.

So, you have a 50% chance of having AaBbCc offspring.

a

explanation:

many plants naturally reproduce this way, but it can also be induced artificially. horticulturalists have developed asexual propagation techniques that use vegetative plant parts to replicate plants. success rates and difficulty of propagation vary greatly. monocotyledons typically lack a vascular cambium and therefore are harder to propagate.