The stage of cellular respiration shown in the image is the glycolysis. It is the first step of the cellular respiration that occurs in the cytoplasm of the cell. It is a sequence of reactions catalysed by various enzymes. During glycolysis 6-carbon glucose is converted into two 3-carbon pyruvic acids. Glycolysis begins with activation of glucose. It is activated by using 2ATP and at the end of glycolysis 4ATPs are formed. Thus, net gain of ATP is 4 -2 = 2ATP.
Although we don't have the diagram, the stage of cellular respiration in which a glucose molecule is converted into 2 pyruvic acid molecules is glycolysis. A diagram showing the process is attached.
Have look at the ATPs involved in the reaction. You can see in the first stage there are 2 ATPs required to begin the reaction (the arrow points inwards). Then, in the second stage, in the conversion the 2 x 3C sugar phosphates, there are 2 ATPs released each.
So we have made 4 ATP, but we had to use 2 ATP, that means the net ATP production is 2 ATP (and the gross ATP production would be 4).
At glycolysis stage, the net ATP production is 2 ATP.
d. 36 atp is the correct answer.
I wanna say D, but I’m not entirely sure
net atp production at cellular respiration:
usually prokaryotic cells produce the maximum number of atp molecules in other hand eukaryotic cells produce 36 atp molecules only.
in eukaryotes the nadh molecules produced in glycolysis process passes through the mitochondrial membrane by that it costs 2 atp molecules, therefore the 38 atp's produced reduced by 2.
the answer is 2 ATP on edg 2020
The correct answer is 2 atp
The last answer is correct if am sure.