The isotope chlorine-36 decays into argon-36, with a half-life of 3.01 × 105 years. based on this information, fill in the blanks. a particular sample contains 3 × 1012 atoms of chlorine-36. after 9.03 × 105 years, there will × 10 atoms of chlorine-36 and × 10 atoms of argon-36.

After 9.03 × 105 years, there will 0.37 × 1012 atoms of chlorine-36 and 2.602 × 1012 atoms of argon-36.

Half life an element is the time after which it decays to half of its initial concentration.

Half life of chlorine-36 is 3.01 * 105. And chlorine decays to Argon-36.

So 9.03 * 105 means, There are 3 half life of Chlorine.

                             The amount of chlorine-36 = 1.5 * 1012

                             The amount of Argon-36 = 1.5 * 1012

                              The amount of chlorine-36 = 0.75 * 1012

                               The amount of Argon-36 = 2.25 * 1012

                                The amount of chlorine-36 = 0.372 * 1012

                                 The amount of total Argon-36 = 2.602 * 1012

A particular sample contains of chlorine-36. After , there will atoms of chlorine-36 and atoms of argon-36.

Explanation:

Number of isotope chlorine-36 atoms =

Half-life of  chlorine-36 atoms =

Number of chlorine-36 atom after time , t = N

t =

Number of chlorine-36 atom after time =

Number  of argon-36 atom after time :